One mole of any gas at a given temperature and pressure has same fixed volume and is better known as its Molar gas volume.
In order to to compare the molar volume of gases, chemists use a fixed reference of temperature and pressure. This is called as
"Standard temperature and pressure (abbreviated as S.T.P)".The standard temperature used is 273 Kelvin or 0
o C and the standard pressure is 1 atmospheres (760 mm Hg). At STP we find experimentally that one mole of any gas occupies a volume of 22.4 liters. The equation can be written as
1 mole of a gas at STP = 22.4 liters of a gas
According to the ideal gas law, and the three simple gas laws
- Boyle's Law : V ∞ 1/P (T, n constant)
- Charle's Law : V ∞ T (n, P constant)
- Avogadro's Law : V ∞ n ( P, T constant)
These three laws can be combined into a single more general law
V ∞ n T / P
This is called as Universal Gas Law. It is also called Ideal Gas Law as it applies to all gases which exhibit ideal behavior. i.e, obey the gas laws perfectly. The ideal gas law may be stated as
"The volume of a given amount of gas is directly proportional to the number of moles of gas, directly proportional to the temperature and inversely proportional to the pressure."
Introducing the proportionality constant R in the expression (1), we can write
V = R n T/P
P V = n R T
Molar volume is considered to be
the volume occupied by one mole of any gas at a given pressure and temperature. This is denoted by V
m.
The Molar volume unit is found to be litre per mole or milliliter per mole.
The Molar volume determination of any substance is invariably depending on temperature and pressure.
As per the Avogadro law, "at constant temperature and pressure equal volumes of any gas would contain equal number of molecules." This leads to the assumption that equal number of molecules of any gas, should occupy the same volume, provided there is constant temperature and pressure.
Example of oxygenMass of 1 liter of oxygen at STP = 1.59 g
Mass of 1 mole of oxygen = 32 g
Volume : Mass
1 liter : 1. 59 g
x : 32 g
'x' = (32 / 1.59) litres = 20.126 litres
The table given below provides the relationship existing between Gram Molecular Weight
(GMW), moles, the molar volume and the number of particles of
gases at standard temperature pressure.
| Gas | Molecular Formula | GMW
(in g) | No.of Moles | Molar Volume
dm3 or l | No.of moles in 1 mole |
| Hydrogen | H2 | 2 | 1 | 22.4 | 6.023x 1023 |
| Oxygen | O2 | 32 | 1 | 22.4 | 6.023x 1023 |
| Nitrogen | N2 | 28 | 1 | 22.4 | 6.023x 1023 |
| Chlorine | Cl2 | 71 | 1 | 22.4 | 6.023x 1023 |
| Carbon dioxide | CO2 | 44 | 1 | 22.4 | 6.023x 1023 |
| Nitrogen dioxide | NO2 | 46 | 1 | 22.4 | 6.023x 1023 |
| Ammonia | NH3 | 17 | 1 | 22.4 | 6.023x 1023 |
| Methane | CH4 | 16 | 1 | 22.4 | 6.023x 1023 |
| Sulphur dioxide | SO2 | 64 | 1 | 22.4 | 6.023x 1023 |
Standard molar volume of a gas is the volume occupied by 1 mole of any gas at 273 K and 1 atmospheric pressure (STP). It is equal to 22.4 liters of 22,400 ml. It is the same for all gases.
S.T.P. = Standard Temperature and Pressure
Standard Temperature = 0oC or 273 K
Standard Pressure = 1 atm or 760 mm of mercury
When a liquid is present in a mixture, the volume of one component depends upon the molecules that are surrounding that particular liquid. Partial molar volume is the volume contributed by any particular component in the mixture. So, if A and B are present in a mixture, the partial molar volume will be given both with respect to A and with respect to B.
Thus, Partial molar volume of A would be: Change in volume of the mixture, per mole of A added to it. This can be best represented with the help of one solvent, say water, added to another solvent, like Benzene or ether.
Partial molar volume of B would be: Change in the volume of the mixture per mole of B added to it.
We know that volume occupied by one mole of a gas is its molar volume. This applies to a liquid and a solid too. So, Molar volume of water, a liquid is the volume occupied by one mole of water, in any form. So, 1 mole of water occupies 18 grams. Since density of water is almost equal to 1, we take the grams of water as volume of water. So, Molar volume, or the volume occupied by one mole of water would be 18 milliliters.
Now, what would be the partial volume of water in a mixture?
To give an example for partial molar volume, let us take two solvents
When we add one mole of water to 100 liters of water already present in a vessel, the volume of the liquid will increase by 18 ml. So, this shows that water has a partial molar volume of 18ml/mol in that mixture.
When we add the same one mole of water to 1000ml of Ethanol, instead of 18 ml increase, the volume of the mixture was raised only by 14 ml. So, the partial molar volume depends upon the degree of solvation or the number of moles of surrounding water particles per one mole of water particle.
Below are the solved examples on calculating molar volume -
Solved Examples
Question 1: Find out the volume contained by 6.8 g of ammonia at STP. (N=14, H=1)
Solution:
Gram molecular mass of NH3 = [N = 1 x 14)] + [H = (3 + 1)] = 14 + 3 = 17 g
The mass of 1 mole of NH3 = 17g
Molar volume = 22.4 liters
Volume of 6.8 g of ammonia at STP = ?
The ratio between mass and volume is as follows:
17 g : 22.4 liters
6.8 g : x
x = (6.8 x 22.4) / 17 = 8.96 Liters
Volume occupied by 6.8 g of ammonia at STP = 8.96 liters
Question 2: 112 ml of CO2 has a mass at 0.22 g at standard conditions. What would be the molar mass of CO2.
Solution:
Mass of 112 ml of CO2 at STP = 0.22 g
Mass of 22400 ml of CO2 = ?
The ratio of mass to volume is as follows
0.22 g : 112 ml
x g : 22400 ml
'x' g = (0.22 x 22400) / 112 = 44 g
The mass of 22400 ml of CO2 at STP = 44 g
The molar mass of CO2 = 44 g per mole
Question 3: One gram of pure SO2 has a volume of 450 ml at STP. What would be the Relative Molecular Mass of SO2.
Solution:
Volume of sulfur dioxide gas = 450 ml at STP
Mass of sulfur dioxide gas = 1 g
Mass of one mole of sulfur dioxide = x g/mole
Volume of 1 mole of sulfur dioxide = 22400 ml at STP
Mass : Volume
1 : 450 ml
x : 22400 ml
x = (22400 x 1) / 450 = 49.78
Mass of 1 mole of SO2 = 49.78 g/mole
Relative molecular mass of sulfur dioxide = 49.78
Question 4: Find the mass of 1 mole of CO, if 150 ml of CO contains a mass of 0.225 g at standard conditions.
Solution:
The CO volume = 150 ml
The mass of CO = 0.225 g
The molar volume = 22400 ml
Mass of 1 mole of CO = ?
The ratio between mass and volume is as follows
150 ml : 0.225 g
22400 ml : x g
'x' = (22400 x 0.225) / 150 = 33.6 g
Mass of one mole of CO = 33.6 g/mole
Relative molecular mass of CO = 33.6